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17 April, 01:36

Write the equation in standard form for the circle x2+y2-2y-43=0.

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Answers (2)
  1. 17 April, 03:12
    0
    x^2 + y (y - 2) = 43

    Step-by-step explanation:

    Step 1: Add 43 to both sides

    x^2 + y^2 - 2y - 43 + 43 = 0 + 43

    x^2 + y^2 - 2y = 43

    Step 2: Pull out the y from y^2 - 2y

    x^2 + y^2 - 2y = 43

    x^2 + y (y - 2) = 43

    Answer: x^2 + y (y - 2) = 43
  2. 17 April, 04:06
    0
    The general equation of a circle is:

    (x-a) ² + (y-b) ²=r², where a and b are the coordinates of the center, and r is the radius.

    Now: x²+y²-2y-43=0

    x²+y²-2y+1-44=0

    Sqrt (44) = 6.63, so we get:

    Answer: x² + (y-1) ²=6.63²
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