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17 May, 11:08

How do you solve (2x-8) (4x+1)

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Answers (2)
  1. 17 May, 11:23
    0
    At first you multiple 2x by 4x, than 2x by 1, than you do the same thing, but replace 2x with - 8. After you finished multiplication combine all the monomials together. The answer should be 8x2-30x-8
  2. 17 May, 11:53
    0
    8x^2-30x-8

    Step-by-step explanation:

    2x times 4x = 8x squared

    2x times 1 = 2x

    -8 times 4x = - 32x

    -8 times 1 = - 8

    8x quared + 2x + - 32x + - 8

    = 8x squared - 30x - 8
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