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20 November, 16:41

Let f (x) = 4x+1 and g (x) = 3/4. evaluate each expression symbolically.

a) (f+g) (4)

b) (f-g) (1/4)

c) (fg) (5)

d) (f/g) (0)

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Answers (1)
  1. 20 November, 18:42
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    a. 20 b. 1 13/16 c. 78 3/4 d. undefined

    Step-by-step explanation:

    since f (x) = 4x+1 and g (x) = 3x/4

    a) (f+g) (4)

    = f (4) + g (4)

    f (4) = 4 (4) + 1 = 17

    g (4) = 3 (4) / 4 = 3

    therefore

    (f+g) (4) = 17 + 3 = 20

    b) (f-g) (1/4)

    = f (1/4) - g (1/4)

    f (1/4) = 4 (1/4) + 1 = 2

    g (1/4) = 3 (1/4) / 4 = 3/16

    therefore

    (f-g) (1/4) = 2 - 3/16 = 29/16 = 1 13/16

    c) (fg) (5)

    = f (5) x g (5)

    f (5) = 4 (5) + 1 = 21

    g (5) = 3 (5) / 4 = 15/4

    therefore

    (fg) (5) = 21 x 15/4 = 315/4 = 78 3/4

    d) (f/g) (0)

    = f (0) / g (0)

    f (0) = 4 (0) + 1 = 1

    g (0) = 3 (0) / 4 = 0

    therefore

    (f/g) (0) = 1 / 0 = undefined
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