Find the real solutions of the equation. 8 x Superscript 2 divided by 3 Baseline minus 63 x Superscript 1 divided by 3 Baseline minus 8 equals 0 What is the solution set? Select the correct choice below and fill in any answer boxes within your choice.

- ((sq. rt. 4737) - 63) / 16 & ((sq. rt. 4737) - 63) / 16

Step-by-step explanation:

8x^2/3 - 63x^1/3 - 8 = 0

Have to use the quadratic formula

(-b + - sq. rt. b^2-4ac) / 2a

gives - ((sq. rt. 4737) - 63) / 16

and ((sq. rt. 4737) - 63) / 16

where a = 8/3, b = - 63/3, & c = - 8

hope that's right.