Divide using synthetic division.

x^4 - 4x^3 + x.^2 + 2/

x - 2

2x^3 - 2x^2 - 3x - 6 - (4/x^4 - 4x^3 + x^2 + 2)

Step-by-step explanation:

x-2 = 0

since there is a missing x you have to put in a 0

2 | 1 - 4 1 0 2

1 2 - 4 - 6 - 6

1 - 2 - 3 - 6 - 4

x^3 x^2 x # remainder

bring down the 1 then multiply by 2 then add to - 4

take the - 2 multiply by 2 and add to 1 continuously do the samething

now take all the x's and go down one since you're taking out a x

put ing standard form

2x^3 - 2x^2 - 3x - 6 - (4/x^4 - 4x^3 + x^2 + 2)

i beleive that's the answer, good luck on whatever you're doing

Answer: x-5