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23 April, 17:17

If a square + b square + c square=90, a+b+c=20 find the value of ab+bc+ca

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  1. 23 April, 20:03
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    Answer: ab + bc + ac = 155

    Step-by-step explanation:

    Given: a² + b² + c² = 90 and a + b + c = 20

    Square the second equation, subtract it from the first equation, then simplify.

    Square the second equation:

    (a + b + c) ² = 20²

    a² + b² + c² + 2ab + 2bc + 2ac = 400

    Subtract the equations:

    a² + b² + c² + 2ab + 2bc + 2ac = 400

    - (a² + b² + c² = 90)

    2ab + 2bc + 2ac = 310

    Simplify:

    2 (ab + bc + ac) = 310

    :2 : 2

    ab + bc + ac = 155
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