Calculate the potential energy associated with 1 m^3 of water at 607 feet tall taking the mass of 1 m^3 of water to be 1000 kg

1813.137 KJ

Step-by-step explanation:

potential energy of the body = mgH

where m is mass in Kg, g = 9.81 m/sec^2 and H = height in m

here m = 1000 kg, g = 9.81 m/s^2 and H = 607 feet = 607*0.305 = 185.135 m

hence the potential energy p = 1000*9.81*185.135 = 1813137.2 J

= 1813.137 KJ

hence the potential energy associated with 1 m^3 of water at 607 feet tall taking the mass as 1000 kg is = 1813.137 KJ