Dawna walks 10 miles starting at 1:00 p. m. every day. On average she finishes at 3:50 p. m., with a standard deviation of 10 minutes. Jeanne leaves 30 minutes later, and every day she runs 10 miles exactly twice as fast as Dawna walks on that day. What is the mean time Jeanne will finish and the standard deviation of the number of minutes it takes Jeanne to finish? (A) mean 2:25 p. m., standard deviation 5 minutes (B) mean 2:25 p. m., standard deviation 20 minutes (C) mean 2:25 p. m., standard deviation 35 minutes (D) mean 2:55 p. m., standard deviation 5 minutes (E) mean 2:55 p. m., standard deviation 35 minutes
+1
Answers (1)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Dawna walks 10 miles starting at 1:00 p. m. every day. On average she finishes at 3:50 p. m., with a standard deviation of 10 minutes. ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Home » Mathematics » Dawna walks 10 miles starting at 1:00 p. m. every day. On average she finishes at 3:50 p. m., with a standard deviation of 10 minutes. Jeanne leaves 30 minutes later, and every day she runs 10 miles exactly twice as fast as Dawna walks on that day.