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3 June, 05:58

A school is building a rectangular soccer field that has a perimeter of 340 yards. the soccer field must be 50 yards longer than its width? a. create a let statement and an equation for the given situation?

b. solve your equation to find the length and width of the field in yards

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  1. 3 June, 08:43
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    A. Let

    L = length of a rectangular soccer field

    W = width of a rectangular soccer field

    P = perimeter of a rectangular soccer field

    L = W + 50 (the length is longer than the width)

    For the equation, the formula for a perimeter of the rectangle is

    2L + 2W = P

    Since the length and perimeter are given, substitute them as

    2 (W + 50) + 2W = 340

    b. Solving for W,

    2 (W + 50) + 2W = 340

    2W + 100 + 2W = 340

    2W + 2W = 340 - 100

    4W = 240

    (4W) / 4 = 240/4

    W = 60 yards

    Solving for L,

    L = 60 + 50 = 110 yards

    The rectangular soccer field has the length of 110 yards and the width of 60 yards.
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