a laboratory employee is mixing a 10% saline solution with a 4% saline solution. how much of each solution is needed to make 500 ml of a 6% solution

Question

Mathematics

Vance Williams

6 June, 09:32

a laboratory employee is mixing a 10% saline solution with a 4% saline solution. how much of each solution is needed to make 500 ml of a 6% solution

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Rudy · Answer 1

Step-by-step explanation:

let he 10 % solution = x ml

0.1 0 x + (500-x) * 0.04=500*0.06

0.10 x+20-0.04 x=30

0.06 x=30-20

0.06 x=10

x=10 / (0.06) = 1000/6=500/3 ml=166 2/3 ml

so 10 % solution is 166 2/3 ml

4 % solution=500 - 500/3=1000/3=333 1/3 ml