Ask Question
4 July, 02:36

Factor. 25m100-121n16 (5m50-11n8) (5m50+11n8) (5m50-11n8) 2 (5m10-11n4) 2 (5m10-11n4) (5m10+11n4)

+4
Answers (1)
  1. 4 July, 05:03
    0
    The answer to your question is (5m50-11n8) (5m50+11n8)

    Step-by-step explanation:

    25m¹⁰⁰-121n¹⁶

    find the prime factors of 25 and 100

    25 5 121 11

    5 5 11 11

    1 1

    25 = 5 x 5 = 5² 121 = 11 x 11 = 11²

    m¹⁰⁰ = (m⁵⁰) ² n¹⁶ = (n⁸) ²

    Substitution

    25m¹⁰⁰-121n¹⁶ = 5² (m⁵⁰) ² - 11² (n⁸) ²

    = (5m⁵⁰ - 11n⁸) (5m⁵⁰ + 11n⁸)

    (5m50-11n8) (5m50+11n8)

    (5m50-11n8) 2

    (5m10-11n4) 2

    (5m10-11n4) (5m10+11n4)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Factor. 25m100-121n16 (5m50-11n8) (5m50+11n8) (5m50-11n8) 2 (5m10-11n4) 2 (5m10-11n4) (5m10+11n4) ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers