Factor. 25m100-121n16 (5m50-11n8) (5m50+11n8) (5m50-11n8) 2 (5m10-11n4) 2 (5m10-11n4) (5m10+11n4)

The answer to your question is (5m50-11n8) (5m50+11n8)

Step-by-step explanation:

25m¹⁰⁰-121n¹⁶

find the prime factors of 25 and 100

25 5 121 11

5 5 11 11

1 1

25 = 5 x 5 = 5² 121 = 11 x 11 = 11²

m¹⁰⁰ = (m⁵⁰) ² n¹⁶ = (n⁸) ²

Substitution

25m¹⁰⁰-121n¹⁶ = 5² (m⁵⁰) ² - 11² (n⁸) ²

= (5m⁵⁰ - 11n⁸) (5m⁵⁰ + 11n⁸)

(5m50-11n8) (5m50+11n8)

(5m50-11n8) 2

(5m10-11n4) 2

(5m10-11n4) (5m10+11n4)