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MathematicsMathematics
18 February, 22:57

Solve the Equation x^5-5x^3+4x=0

a) 0, (-/+) 1, (-/+) 3

b) 0, (-/+) 2, (-/+) 3

c) 0, (-/+) 1, (-/+) 2

d) 0, (-/+) 2, (-/+) 4

+1
Answers (1)
  1. 19 February, 02:36
    0
    x = 2 or x = 1 or x = 0 or x = - 1 or x = - 2

    Step-by-step explanation:

    Solve for x:

    x^5 - 5 x^3 + 4 x = 0

    The left hand side factors into a product with five terms:

    x (x - 2) (x - 1) (x + 1) (x + 2) = 0

    Split into five equations:

    x - 2 = 0 or x - 1 = 0 or x = 0 or x + 1 = 0 or x + 2 = 0

    Add 2 to both sides:

    x = 2 or x - 1 = 0 or x = 0 or x + 1 = 0 or x + 2 = 0

    Add 1 to both sides:

    x = 2 or x = 1 or x = 0 or x + 1 = 0 or x + 2 = 0

    Subtract 1 from both sides:

    x = 2 or x = 1 or x = 0 or x = - 1 or x + 2 = 0

    Subtract 2 from both sides:

    Answer: x = 2 or x = 1 or x = 0 or x = - 1 or x = - 2
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Home » Mathematics » Solve the Equation x^5-5x^3+4x=0 a) 0, (-/+) 1, (-/+) 3 b) 0, (-/+) 2, (-/+) 3 c) 0, (-/+) 1, (-/+) 2 d) 0, (-/+) 2, (-/+) 4
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