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4 September, 20:55

A=16, c=14 find the length of b if necessary round to the nearest tenth

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  1. 4 September, 23:53
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    Step-by-step explanation:

    Assuming you mean sides of a right triangle, we can use the Pythagorean theorem (A^2 + B^2 = C^2)

    We have A and B, so we can plug those into the equation.

    (16) ^2 + B^2 = (14) ^2

    (16) ^2 is 256 and (14) ^2 is 196. Plug those in.

    256 + B^2 = 196

    Get rid of the 256 by subtracting.

    B^2 = 196 - 256

    B^2 = - 60

    √B^2 = √-60

    You can't take the square root of a negative number, so the solution is not possible. We can confirm because C cannot be bigger than A or B.
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