4. A rectangle has a width of 2 cm and a perimeter of 25 cm. Find the length and the area.

A) ℓ = 12.5 cm and A = 21 cm2

B) ℓ = 10.5 cm and A = 25 cm2

C) ℓ = 10.5 cm and A = 21 cm2

D) ℓ = 12.5 cm and A = 25 cm2

l = 10.5 cm and A = 21 cm2

Step-by-step explanation:

Area is w*l

Perimeter is 2 (w+l)

Replacing the information known in the problem you can get the length with the perimeter

P = 2 (w+l)

25 = 2 (2+l)

12.5 = 2 + l

10.5 cm = l

with the length now you can find the area

A = w*l

A = 2*10.5

A = 21 cm2