A right triangle has sides of length 3, 4, and.

Find if it is the hypotenuse.

Find if it is one of the legs.

Solution:

Let the third side be = x

Case 1. Find it if it's the hypotenuse.

Solution : Pythagoras Theorem = (H) ² = (P) ² + (B) ²

= On substituting the values = (n) ² = 4²+3²

= x²=16+9

= x² = 25

= x=√25

= x = 5

Case 2. Find it if it's one of the legs

= If it is one of the legs, then the longest side of them will be the hypotenuse which is 4.

Legs = 3, n

Hypotenuse = 4

Pythagoras Theorem = (P) ² + (B) ² = (H) ²

= 3²+x²=4²

= 9+x² = 16

= x² = 16-9

= x² = 7

= x = √7

= x = 2.64 (approx.)

5/hypotenuse, the square root of 7 / leg

Step-by-step explanation:

3^2+4^2=25 or 5^2. you use a^2+b^2=c^2. it would be one of the hypotenuses. If the missing number is a leg, you would do 4^2=3^2+x^2. 16=9+x^2, 7=x^2, so you plug in the numbers differently.