Find the area of the hexagen whose Vertices taken in order

are (5.0), (4,2), (1,3), (-2,2), (-3,-1) and (o,-47)

Step-by-step explanation:

A (5,0), B (4,2), C (1,3), D (-2,2), E (-3,-1), F (0-4)

we divide the hexagon in triangles and trapeziums

area Δ BCD (with coordinates B (4,2), C (1,3), D (-2,2)) = 1/2 (2+4) * 2=6

area Δ DEG (with coordinates D (-2,2), E (-3,-1), G (-2.-2)) = 1/2 (2+2) * 2=4

area ΔAOF (with coordinates A (5,0), O (0,0), F (0,-4)) = 1/2*5*4=10

area trapezium ABDH (with coordinates A (5,0), B (4,2), D (-2,2), H (-2,0)) = 1/2[ (2+5) + (2+4) ]*2=13

area trapezium OHGF (with coordinates O (0,0), H (-2,0), G (-2,-2), F (0,-4)) = 1/2[4+2]*2=6

Total area=6+4+10+13+6=39 sq units.