Ask Question
19 February, 00:30

A bag contains 4 blue and 6 green marbles. Two marbles are selected at random from the bag. If the first marble is NOT replaced before the second marble is drawn, what is the P (blue second | green first) ?

+2
Answers (1)
  1. 19 February, 01:34
    0
    I think it's 4/10

    Step-by-step explanation:

    P (B|G) = p (BnG) / p (G) =

    P (4x6) / 6 4x6=24.

    24/6 = 4/10
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A bag contains 4 blue and 6 green marbles. Two marbles are selected at random from the bag. If the first marble is NOT replaced before the ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers