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18 November, 03:55

What are the roots of the equation x^2+6x-9=10?

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  1. 18 November, 07:52
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    -3+2sqrt7

    -3-2sqrt7

    Step-by-step explanation:

    x^2+6x-9=10

    x^2+6x-9-10=0

    x^2+6x-19=0

    ax^2+bx+c=0

    a=1 b=6 c=-19

    As cannot be solved by completing square we will use quadratic equation

    x = (-b+sqrt (b^2-4ac)) / 2a and x = (-b-sqrt (b^2-4ac)) / 2a

    x = (-6+sqrt (6^2-4*-19)) / 2 and x = (-6-sqrt (6^2-4*-19)) / 2

    x = (-6+sqrt (36+76)) / 2 and x = (-6-sqrt (36+76)) / 2

    x = (-6+4sqrt7) / 2 and x = (-6-4sqrt7) / 2

    x = (-3+2sqrt7) and x = (-3-2sqrt7)

    x=2.29 and x = - 8.29
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