Find the center, vertices, and foci of the ellipse with equation x squared divided by 400 plus y squared divided by 625 = 1

x^2/400 + x^2/625

(x-0) ^2/400) + (y-0^2/625)

x^2=400

X=sqrt. 400

x = 20

y^2=625

y = sqrt. 625

y = 25

a^2-c^2=b^2

sqrt 400-625 = c

20-25=c

The correct answer is c=-5

(-5,0)

(5,0)

Center: (0, 0); Vertices: (0, - 25), (0, 25); Foci: (0, - 15), (0, 15)

Step-by-step explanation:

The center is (0,0) because there is no (h, k)

The vertices are (0, - 25), (0, 25) because we use the formula (x-h) ^2/b^2 + (y-k) ^2/a^2 = 1, since the y's denominator is larger.

The foci are (0, - 15), (0, 15) because we use the formula a^2=b^2+c^2 to find the foci, a=625 and b=400, simplify to c= + or - 15 and you get your foci.