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15 August, 11:42

The sum of four times a first number and a second number is 68. If the first number is decreased by twice the second number the result is - 1. Find the numbers.

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  1. 15 August, 13:11
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    The first number is 15 and the second number is 8.

    Step-by-step explanation:

    Let us assume,

    First number be 'x'. Second number be 'y'.

    Given:

    Sum of four times a first number and a second number is 68.

    ⇒ 4x + y = 68

    ⇒ y = 68-4x

    If the first number is decreased by twice the second number the result is - 1.

    ⇒ x - 2y = - 1

    Substitute y = 68-4x in the above equation.

    ⇒ x - 2 (68-4x) = - 1

    ⇒ x-136+8x = - 1

    ⇒ 9x - 136 = - 1

    ⇒ 9x = - 1+136

    ⇒ x = 135/9

    ⇒ x = 15

    The first number is 15.

    The second number is y = 68-4x.

    ⇒ y = 68 - 4 (15)

    ⇒ y = 68-60

    ⇒ y = 8

    The second number is 8.
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