Solve the following pair of simultaneous equations.

2x + 3y = 6

3x - 2y = 22

The answer for the first one is y=-2/3x+2 and the second one is y=3/2x-11

(6, - 2)

Step-by-step explanation:

Given the 2 equations

2x + 3y = 6 → (1)

3x - 2y = 22 → (2)

Eliminate the y - term by multiplying (1) by 2 and (2) by 3

4x + 6y = 12 → (3)

9x - 6y = 66 → (4)

Add (3) and (4) term by term

13x = 78 (divide both sides by 13)

x = 6

Substitute x = 6 into either of the 2 equations and solve for y

Using (1), then

(2 * 6) + 3y = 6

12 + 3y = 6 (subtract 12 from both sides)

3y = - 6 (divide both sides by 3)

y = - 2

Solution is (6, - 2)