Ask Question
26 December, 11:30

Given the function ƒ (x) = 2x3 - 7x2 - 5x + 1, find ƒ (-2).

+5
Answers (2)
  1. 26 December, 13:12
    0
    C. - 33

    Step-by-step explanation:

    ƒ (x) = 2x3 - 7x2 - 5x + 1

    ƒ (-2) = 2 (-2) 3 - 7 (-2) 2 - 5 (-2) + 1 → ƒ (-2) = - 16 - 28 + 10 + 1

    ƒ (-2) = - 33
  2. 26 December, 14:22
    0
    2 (-2) ^3-7 (-2) ^2-5 (-2) + 1

    2 (-8) - 7 (4) + 10+1

    -16-28+11

    -44+11 = - 33 is the answer
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Given the function ƒ (x) = 2x3 - 7x2 - 5x + 1, find ƒ (-2). ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers