Ask Question
27 November, 04:44

find three consecutive odd integers such that the product of the first and third is 71 more than 10 times the second

+5
Answers (1)
  1. 27 November, 06:09
    0
    13, 15, 17

    Step-by-step explanation:

    x (x + 4) = 10 (x + 2) + 71

    x2 + 4x = 10x + 20 + 71

    x2 - 6x - 91 = 0

    (x + 7) (x - 13) = 0

    x + 7 = 0

    x = - 7

    -7, - 5, - 3

    x - 13 = 0

    x = 13

    13, 15, 17
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “find three consecutive odd integers such that the product of the first and third is 71 more than 10 times the second ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers