Three pirates named Ahab sparrow and Davy play a game. The pirates have total of 210 coins, and each pirate has a different number of coins. At the end of the game, Ahab has won 5 coins and Davy has won 7 coins. Now, the ratio of coins belonging to Ahab, sparrow and Davy is 4:5:6. How many coins did sparrow have at the beginning?

Question

Mathematics

Guest

8 August, 12:55

Three pirates named Ahab sparrow and Davy play a game. The pirates have total of 210 coins, and each pirate has a different number of coins. At the end of the game, Ahab has won 5 coins and Davy has won 7 coins. Now, the ratio of coins belonging to Ahab, sparrow and Davy is 4:5:6. How many coins did sparrow have at the beginning?

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Alana Morton · Answer 1

No of coins Sparrow had in the beginning 92 coins

Step-by-step explanation:

Total coins = 210

Current ratio = 4:5:6

It implies 210 needs to be split into 15 parts (4+5+6)

So, each part = 210/15 = 14 coins

Again which implies 14*4 : 14*5 : 14*6 = 56 : 70 : 84

So before the game began,

No of coins Ahab had = (56 - 5) = 51

No of coins Davy had = (84 - 7) = 67

Hence, No of coins Sparrow had = (210 - 51 - 67) = 92 coins