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13 November, 01:45

How much pure water must be mixed with 10 liters of a 25% acid solution to reduce it to a 10% acid solution?

25 L

11 L

15 L

+1
Answers (1)
  1. 13 November, 04:46
    0
    15 L

    Step-by-step explanation:

    If x is the liters of pure water, then:

    0x + 0.25 (10) = 0.10 (x + 10)

    2.5 = 0.10x + 1

    1.5 = 0.10x

    15 = x
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