What kinetic energy has a 4kg shootput thrown with a velocity of 12m/s

288J

Step-by-step explanation:

recall the formula for kinetic energy

KE = (1/2) mv²

where m is the mass ( = 4kg) and v is the velocity (=12 m/s)

hence

KE = (1/2) (4) (12) ² = 288J

Answer: 288 Joules

Step-by-step explanation:

K. E = 1/2 * mass * square of the velocity

K. E = 1/2 * m * v ^ 2

From the question:

Mass = 4kg

Velocity = 12m/s

Therefore:

K. E = 1/2 * 4 * 12^ 2

= 0.5 * 4 * 144

= 288 Joules