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21 November, 10:11

Which is the graph of f (x) = - (x + 3) (x + 1) ?

On a coordinate plane, a parabola opens down. It goes through (0, negative 3), has a vertex at (2, 1), and goes through (4, negative 3).

On a coordinate plane, a parabola opens down. It goes through (negative 3, 0), has a vertex at (negative 2, 1), and goes through (negative 1, 0).

On a coordinate plane, a parabola opens up. It goes through (negative 4, 3), has a vertex at (negative 2, negative 1), and goes through (0, 3).

On a coordinate plane, a parabola opens up. It goes through (0, 3), has a vertex at (2, negative 1), and goes through (4, 3).

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Answers (2)
  1. 21 November, 13:51
    0
    1.) maximum value

    2.) for no values of x

    3,) when x > - 1

    4.) all real numbers

    5.) all numbers less than or equal to 0

    I did the workStep-by-step explanation:

    i just did this on edg
  2. 21 November, 13:53
    0
    The 2nd answer choice is the correct one.

    Step-by-step explanation:

    f (x) = - (x + 3) (x + 1), when multiplied out, becomes f (x) = - (x^2 + 4x + 3), or

    f (x) = - x^2 - 4x - 3. Because of the - sign, the graph opens downward.

    Because of the factor (x + 3), the graph goes through (-3, 0).

    Because of the factor (x + 1), the graph goes through (-1, 0).

    The vertex is located horizontally exactly betwen x = - 3 and x = - 1, that is, at x = - 2. Since f (-2) = - (-2) ^2 - 4 (-2) - 3, the max value of f is - 4 + 8 - 3, or 1. Thus, the vertex is located at (-2, 1). This matches the 2nd answer choice.
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