In a small private school, five students are randomly selected from eighteen available students. What is the probability that they are the five youngest students?

1 / 8568

Step-by-step explanation:

The number of combinations is:

₁₈C₅ = (18! / (5! (18-5) !)

₁₈C₅ = 8568

There are 8568 possible groups of 5 that can be selected from 18. Only 1 of those groups contains the five youngest students. So the probability is:

P = 1 / 8568 ≈ 0.0117%