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31 January, 05:06

Which is the area between the x-axis and y=x from x=3 to x=6

63

45/2

27/2

81

+3
Answers (1)
  1. 31 January, 08:02
    0
    I am going to answer using calculus. Let me know if you instead were looking for an algebraic method. Take the definite integral from 3 to 6 of xdx. [x^2/2]3 to 6 = 18 - (9/2) = (36-9) / 2 = 27/2. The area is 27/2.
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