A rectangle has a length that is 4 units longer than the width. If the width is increased by 7 units and the length increased by 5 units, write an equivalent expression for the area of the rectangle. Group of answer choices

A = (x + 7) (x + 9)

Step-by-step explanation:

Let the width w = x

then length l = w + 4 = x + 4

Area = length x width

= x (x+4)

Then the the width is increased by 7 units and the length increased by 5 units.

w = x + 7

l = (x + 4) + 5 = x + 9

A = (x + 7) (x + 9)

Area of rectangle = length * Width

In this case

Assuming "w" as the width of rectangle,

Area = (w + 9) (w + 7)

Step-by-step explanation:

Let "w" be the width of rectangle,

so

length = w + 4, as it is 4 units greater.

Width = w

Now after adding 5 units in length and 7 units in width, now our measurments will be,

length = w + 4 + 5 = w+9

width = w+7.

So now area will be

A = (w+9) (w+7).