Seperate the number 53 into 3 parts so that the second number is 3 less than the first number and the third number is twice the first number. Give the value of the second number.

Question

Mathematics

Ulises Duarte

4 September, 02:03

Seperate the number 53 into 3 parts so that the second number is 3 less than the first number and the third number is twice the first number. Give the value of the second number.

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Answers (1)

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Zaid · Answer 1

Hello,

Let a the first, b the second and c the third.

a+b+c=53

b=a/3

c=2a

==>a+a/3+2a=53

==>10a/3=53

==>a=15.9

c=2*a=2*15.9=31.8

b=a/3=15.9/3=5.3

Proof: a+b+c=15.9+5.3+31.8=53

The second number is 5.3