A bag contains 6 red jelly beans 4 green jelly beans 4 blue jelly beans

12/91

Explanation:

The question is incomplete. The complete question is:

A bag contains 6 red jelly beans, 4 green jelly beans, and 4 blue jelly beans.

If we choose a jelly bean, then another jelly bean without putting the first one back in the bag, what is the probability that the first jelly bean will be green and the second will be red?

Solution

The probability that the first jelly bean will be green is the number of green jelly beans divided by the total number of jelly beans:

4/14

After chosing the first green jelly bean, there will be 13 jelly beans, from which 6 are red. Thus, the probability that the second jelly bean will be red is:

6/13

The probability of the joint events is the product of the two consecutive events:

(4/14) * (6/13) = 12/91 ← answer