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6 April, 03:10

A certain company consists of 3 numbers followed by 3 letters. The numbers 0 and 2 are not allowed. The letters o and z are also not permitted. How many passwords are possible?

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  1. 6 April, 04:34
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    7,077,888

    Step-by-step explanation:

    Of the 3 numbers, we can have 8 numbers in each position (since 0 and 2 are not allowed from the number 0 - 9 [10 digits]).

    So that would be 8 * 8 * 8 different possibilities

    Now,

    we can have 24 letters in each position (since 0 and z are not allowed form the alphabets a - z [26 letters]).

    So that would be 24 * 24 * 24 different possibilities

    The number of passwords possible would be:

    8 * 8 * 8 * 24 * 24 * 24 = 7,077,888
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