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25 July, 19:44

A classic counting problem is to determine the number of different ways that the letters of "success" can be arranged. Find that number

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  1. 25 July, 21:15
    0
    Answer:420 ways

    Step-by-step explanation:

    Success

    The total = 7!

    S: 3!

    C:2!

    Permutation: 7! / (3!2!)

    : 5040 / (6*2)

    The arrangement will be 420ways
  2. 25 July, 23:25
    0
    Answer: 420 ways

    Step-by-step explanation:

    Given the word "success"

    It consists of:

    3 letter "s" = 3!

    2 letter "c" = 2!

    And a total of 7 letters. = 7!

    The number of ways that the letters can be arranged can be given as;

    N = 7! / (3!) (2!)

    N = 7!/12 = 420 ways
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