A car was travelling at a constant speed of 19 m/s, then accelerated for 10 seconds. The distance travelled, during this time, "d" metres, is given by the formula d = 19t + t^2, where "t" is the time in seconds since the acceleration began. How long did it take the car to travel 200m? Give the answer to the nearest tenth of a second. Solve algebraically.

Question

Mathematics

Sherlyn Salazar

24 February, 06:56

A car was travelling at a constant speed of 19 m/s, then accelerated for 10 seconds. The distance travelled, during this time, "d" metres, is given by the formula d = 19t + t^2, where "t" is the time in seconds since the acceleration began. How long did it take the car to travel 200m? Give the answer to the nearest tenth of a second. Solve algebraically.

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Answers (1)

Know the Answer?

Aden Blackwell · Answer 1

7.5 seconds.

Step-by-step explanation:

Substitute the distace 220m in the given equation:

d = 19t + t^2

200 = 19t + t^2

t^2 + 19t - 200 = 0

t = [-19 + / - sqrt (19^2 - 4*1*-200) ] / 2

t = - 19 + / - sqrt (1161) / 2

t = (-19 + / - 34.07) / 2

t = 7.535 seconds