The sum of three consecutive integers is - 234 find the integers

-77, - 78, - 79

Step-by-step explanation:

let one of the integers be x

since the integers are consecutive, the other 2 integers must be

(x+1) and (x+2)

given that sum of the integers is - 234,

x + (x+1) + (x+2) = - 234

x + x + 1 + x + 2 = - 234

3x + 3 = - 234 (subtract 3 from both sides)

3x = - 234-3

3x = - 237 (divide both sides by 3)

x = - 237 / 3

x = - 79 (answer)

hence the other two numbers are

(x + 1) = - 79 + 1 = - 78 (answer)

and

(x+2) = - 79 + 2 = - 77 (answer)

Step-by-step explanation:

let the first integer is 'x', and by adding 1 in it we get the second integer that is 'x+1', and for third integer we need to add 1 in the previous integer i. e. is 'x+1' we get 'x+2'. Now all three integers we have are

x, x+1 and x+2.

since sum or add all three integer we get - 234. so

x+x+1+x+2=-234

x+x+x=3x, and 1+2=3

3x+3=-234

3x=-234-3

3x=-237

x=-237/3

now the first integer is - 237/3 or - 79,

second integer is - 78 and third integer is - 77.

for verification add all three to get - 234.

-79-78-77=-234. hence proved.