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15 April, 02:55

The area of a playground is 216 yd^2. the width of the playground is 6 yd longer than its length find the length and width.

A. length=18, width=12

B. length=12, width=18

C. length=18, width=24

D. length=24, width=18

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Answers (1)
  1. 15 April, 03:30
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    Let the length of the playground be x, then the width is 6 + x.

    Area = length * width = x * (6 + x) = 6x + x^2 = 216

    Solving the quadratic equation x^2 + 6x - 216 = 0, we have x = 12 or - 18

    i. e length = 12 and width = 6 + 18 = 18
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