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6 June, 16:54

the probability of rolling a die and getting a 6 is of course 1/6 and the probability of not getting a 6 is 5/6. If you roll the same die 8 times, what is the probability that 6 will show up twice?

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  1. 6 June, 17:01
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    0.261

    Step-by-step explanation:

    We use the Bernoulli trial method to solve this. The form of the answer goes thus:

    P = nCr * x^2 * y^6

    Where n is the total number of trials which is 8, while r is the expected number of success, 2 in this case. x is the probability of success 1/6 while y is the probability of failure 5/6 in this case.

    P = 8C2 * (1/6) ^2 * (5/6) ^6

    P = 28 * 0.028 * 0.335 = 0.261
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