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28 June, 22:16

Factor the following polynomial completely. - x2y2 + x4 + 9 y2 - 9 x2 (x - 3) (x - 3) (x + y) (x - y) (x + 3) (x + 3) (x + y) (x - y) (x + 3) (x - 3) (x + y) (x - y)

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  1. 28 June, 22:52
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    (x + 3) (x - 3) (x + y) (x - y)

    Step-by-step explanation:

    You can group the terms in pairs and factor each pair:

    -x^2y^2 + x^4 + 9y^2 - 9x^2 = x^2 (-y^2+x^2) - 9 (-y^2+x^2)

    = (x^2 - 9) (x^2 - y^2)

    Each of these factors is the difference of squares, so can be factored as such:

    = (x + 3) (x - 3) (x + y) (x - y)
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