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9 August, 16:31

Use technology or a z-score table to answer the question.

The scores for a golf tournament are normally distributed with a mean of 210 and a standard

deviation of 80. Ella scored 230 at the tournament

What percent of golfers scored less than Ella?

Round your answer to the nearest whole number

A:60%

B:75%

C:77%

D:80%

+2
Answers (1)
  1. 9 August, 16:36
    0
    Answer: A:60%

    Step-by-step explanation:

    Since the scores for a golf tournament are normally distributed, we would apply the formula for normal distribution which is expressed as

    z = (x - µ) / σ

    Where

    x = scores for the tournament.

    µ = mean score

    σ = standard deviation

    From the information given,

    µ = 210

    σ = 80

    We want to find the probability percent of golfers that scored less than Ella. It is expressed as

    P (x < 230)

    z = (230 - 210) / 80 = 0.25

    Looking at the normal distribution table, the probability corresponding to the z score is 0.5987

    Therefore, the percent of golfers that scored less than Ella is

    0.5987 * 100 = 59.87

    Approximately 60%
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