Which restriction is appropriate for the variable?

3y^2 - 3y/y-1

A. no restrictions are needed

B. y = - 1

C. y = 1

D. y = 3 <---

Question

Bryan Hicks

19 October, 16:24

+2

Answers (1)

Know the Answer?

Lilianna Smith · Answer 1

Best answer is y=1

Because if the denominator is equals to 1, then the answer will be undefined and we don't want it to be undefined.

Which restriction is appropriate for the variable?3y^2 - 3y/y-1A. no restrictions are neededB. y = - 1C. y = 1D. y = 3 <---