Ask Question
8 November, 06:41

When a number is increased by 28%, the result is 47. What is the original number to the nearest tenth?

+3
Answers (1)
  1. 8 November, 07:23
    0
    The original number was 36.7.

    Step-by-step explanation:

    Multipliers:

    The multiplier for a increase of a% is 1 + a/100.

    The multiplier for a decrease of b% is 1 - b/100.

    In this question:

    The original value is x.

    Increased by 28%, so we have that 1 + (28/100) = 1.28x. Equals 47. We have to find x.

    1.28x = 47

    x = 47/1.28

    x = 36.7

    The original number was 36.7.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “When a number is increased by 28%, the result is 47. What is the original number to the nearest tenth? ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers