If the distance covered by an object in time t is given by s (t) = 2t^2+3t, where s (t) is in meters and t is in seconds, what is the average velocity over the interval from 2 seconds to 4 seconds?

Answers:

a) 15m/s

b) 14m/s

c) 13m/s

d) 12m/s

e) 11m/s

a) 15 m/s.

Step-by-step explanation:

s (t) = 2t^2 + 3t

Distance at 2 seconds = s (2) = 2 (2) ^2 + 3 (2) = 14 m.

Distance at 4 seconds = s (4) = 2 (4) ^2 + 3 (4) = 44 m.

Average velocity = distance travelled from t = 2 until t = 4 / time

= (44 - 14) / 4 - 2

= 30/2

= 15 m / s.