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25 November, 23:30

Two is a zero of the equation x3-x2-14x+24=0. Which factored form is equivalent to the equation?

A: (x-3) (x-2) (x+4) = 0

B: (x-3) (x+2) (x+4) = 0

C: (x+4) (x--√2) (x+-√2) = 0

D: (x-2) (x+2) (x+4) = 0

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Answers (1)
  1. 26 November, 03:09
    0
    The answer to your question is: letter A

    Step-by-step explanation:

    x³ - x² - 14x + 24 = 0

    If two is a zero of the polynomial, then x = 2, divide the polynomial by 2.

    Synthetic division

    1 - 1 - 14 + 24 2

    2 2 - 24

    1 1 - 12 0

    Result x² + x - 12 = 0

    Factor the polynomial, find two numbers that multiply gives - 12 and added gives + 1.

    These numbers are + 4 and - 3

    +4 - 3 = + 1

    (+4) (-3) = - 12

    (x + 4) (x - 3) = 0

    Finally

    (x + 4) (x - 3) (x - 2) = 0
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