Ask Question
31 July, 18:53

Solve the system of equations algebraically.

4x - 4y = - 48

5x - 6y = - 65

A) no solution

B) (-6, 4)

C) many solutions

D) (-7, 5)

+3
Answers (1)
  1. 31 July, 19:21
    0
    x = - 7, y = 5 thus D)

    Step-by-step explanation:

    Solve the following system:

    {4 x - 4 y = - 48 | (equation 1)

    5 x - 6 y = - 65 | (equation 2)

    Swap equation 1 with equation 2:

    {5 x - 6 y = - 65 | (equation 1)

    4 x - 4 y = - 48 | (equation 2)

    Subtract 4/5 * (equation 1) from equation 2:

    {5 x - 6 y = - 65 | (equation 1)

    0 x + (4 y) / 5 = 4 | (equation 2)

    Multiply equation 2 by 5/4:

    {5 x - 6 y = - 65 | (equation 1)

    0 x+y = 5 | (equation 2)

    Add 6 * (equation 2) to equation 1:

    {5 x+0 y = - 35 | (equation 1)

    0 x+y = 5 | (equation 2)

    Divide equation 1 by 5:

    {x+0 y = - 7 | (equation 1)

    0 x+y = 5 | (equation 2)

    Collect results:

    Answer: {x = - 7, y = 5
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Solve the system of equations algebraically. 4x - 4y = - 48 5x - 6y = - 65 A) no solution B) (-6, 4) C) many solutions D) (-7, 5) ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers