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15 July, 08:35

Solve for x in the equation x squared minus 8 x + 41 = 0.

x = - 4 ± √37 i

x = - 4 ± 5i

x = 4± √37 i

x = 4 ± 5i

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Answers (1)
  1. 15 July, 09:19
    0
    x = 4 ± 5i

    Step-by-step explanation:

    Just use the quadratic formula (ax²+bx+c=0) like you would for every other quadratic equation. Substitute i² for - 1 when you get the square root of a negative number.

    a = 1

    b = - 8

    c = 41

    Solution is x = (8 ± √ (64-4·41)) / 2

    x = 4 ± (√-100) / 2

    x = 4 ± (√-25·4) / 2

    x = 4 ± √-25

    x = 4 ± √ (25i²)

    x = 4 ± 5i
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