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27 November, 22:14

Evaluate 3+√x+19-√2x when x=6. Write the answer as a decimal. Round to the nearest hundredth if necessary.

A.

4.54

B.

11.46

C.

7

D.

-4

+2
Answers (1)
  1. 28 November, 01:31
    0
    3+√x+19-√2x replace x by 6===> 3+√6+19-√2*6 = 3+√6+19-√12

    Note that √12 = √2x6 = √2 x √6 = = = >3+√6+19 - (√2) x (√6)

    =√6 (1+√2) + 22
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