Solve the system of equations

4x+7y=47

5x-4y=-5

(3,5)

Step-by-step explanation:

To solve the system using the substitution method start by isolating one of the variables in the first equation.

4x+7y-7y=47 - 7y

4x / 4 = (-7y + 47) / 4

x = - 1.75y + 11.75

Next, substitute x = - 1.75y + 11.75 into equation 2 replacing x.

5 (-1.75y + 11.75) - 4y=-5

-8.75y+58.75 - 4y=-5

-8.75y+58.75 - 58.75 - 4y=-5 - 58.75

-8.75y-4y=-63.75

(-12.75y) / -12.75y = (-63.75) / -12.75y

y = 5

Last, substitute y=5 into equation 1 and solve.

4x+7 (5) = 47

4x+35-35=47-35

4x=12

x=3