The sand pit for the long jump has a width of 2.75 meters and a length of 9.54 meters. Just in case it rains, the principal wants to cover the sand pit with a piece of plastic the night before the event. How many square meters of plastic will the principal need to cover the sand pit?

Question

Mathematics

Devon

1 August, 23:16

The sand pit for the long jump has a width of 2.75 meters and a length of 9.54 meters. Just in case it rains, the principal wants to cover the sand pit with a piece of plastic the night before the event. How many square meters of plastic will the principal need to cover the sand pit?

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Answers (1)

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Sanders · Answer 1

The principal will need 26.24 m² of plastic to cover the sand pit.

Step-by-step explanation:

In order to calculate the amount of plastic, we need to find out the area of the sandpit. The shape of the sandpit is a rectangle, so we can use the formula:

A=W*H

where,

W is the width of the sandpit

L is the length of the sandpit

Therefore,

A=2.75 m * 9.54 m = 26.24 m²

The amount of plastic needed is 26.24 m²