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24 June, 03:25

Delia has $945 in 20 dollar and 5 dollar bills. she finds she has 5 times as many 20 dollar bills as 5 dollar bills

a) writing x as the number of 20 dollar bills form an equation to show the info

b) solve the equation to find the number of bills of each type Delia has

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  1. 24 June, 05:40
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    a) 20x + x = 945

    b) Delia has 45 $20 bills and 9 $5 bills.

    Step-by-step explanation:

    a)

    Let x = number of $20 bills.

    "she finds she has 5 times as many 20 dollar bills as 5 dollar bills"

    Since she has 5 times as many $20 bills as $5 bills, that means the number of $5 bills is 1/5 number of $20 bills.

    The number of $5 bills is 1/5 of x, or x/5.

    x number of $20 bills are worth 20x. x/5 number of $5 bills are worth 5 * x/5, or x. The total worth of her bills is 20x + x.

    The total worth of her bills is $945.

    That means that 20x + x must equal $945. That gives us the equation:

    20x + x = 945

    b)

    20x + x = 945

    21x = 945

    Divide both sides by 21.

    x = 45

    x is the number of $20 bills, so she has 45 $20 bills.

    The number of $5 bills is 1/5 the number of $20 bills.

    1/5 of 45 is 9. She has 9 $5 bills.

    Answer: Delia has 45 $20 bills and 9 $5 bills.
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